x^2+4x+4=360

Solution for x^2+4x+4=360 equation:

x^2+4x+4=360

We move all terms to the left:

x^2+4x+4-(360)=0

We add all the numbers together, and all the variables

x^2+4x-356=0

a = 1; b = 4; c = -356;
Δ = b2-4ac
Δ = 42-4·1·(-356)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12\sqrt{10}}{2*1}=\frac{-4-12\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12\sqrt{10}}{2*1}=\frac{-4+12\sqrt{10}}{2}
$